1. The problem involves determining the likelihood (probability) of selecting apples of certain colors from a bag and identifying spinners with equal chances of landing on 1 or 2. 2. For Arun's bag with only red apples: - The likelihood of taking a red apple is 1 because all apples are red. - The likelihood of taking a green apple is 0 because there are no green apples. 3. Probability formula: $$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$$ 4. Since all apples are red, the number of favorable outcomes for red is equal to the total number of apples, so probability is 1. 5. For green apples, favorable outcomes are zero, so probability is 0. 6. For the spinners, we look for those where the chance of spinning a 1 equals the chance of spinning a 2. 7. Analyze each spinner: - A: Circle with 2 sections labeled 1 and 2, equal sections, so equal chance. - B: Hexagon with 6 sections, 1 and 2 are adjacent but only one section each, equal chance. - C: Triangle with 3 sections labeled 1, 2, 3, each section equal, so equal chance. - D: Square with 4 sections labeled 1, 2, 3, but only one section each for 1 and 2, equal chance. - E: Square with 4 sections labeled 1, 2, 3, but arrow points to 3, so not relevant. - F: Pentagon with 5 sections labeled 1, 1, 2, 2, 3; 1 and 2 each have 2 sections, so equal chance. 8. Therefore, spinners A, B, C, D, and F have equal likelihood of spinning a 1 or 2. Final answers: - Likelihood of red apple: 1 - Likelihood of green apple: 0 - Spinners with equal chance of 1 or 2: A, B, C, D, F