1. Stating the problem: We are given the probabilities of choosing socks of different colors: - $P(\text{pink}) = \frac{1}{8}$ - $P(\text{red}) = \frac{1}{6}$ - $P(\text{blue}) = \frac{7}{12}$ - $P(\text{yellow}) = \frac{1}{8}$ We need to find $P(\text{pink or blue})$. 2. Understanding the event $P(\text{pink or blue})$: This represents the probability of selecting either a pink sock or a blue sock. 3. Since the events of choosing pink or blue socks are mutually exclusive (one sock can only have one color), the probability of either event occurring is the sum of their individual probabilities: $$ P(\text{pink or blue}) = P(\text{pink}) + P(\text{blue}) $$ 4. Substitute the given values: $$ P(\text{pink or blue}) = \frac{1}{8} + \frac{7}{12} $$ 5. Find a common denominator to add fractions. The denominators are 8 and 12. The least common denominator (LCD) is 24. Convert each fraction: $$ \frac{1}{8} = \frac{3}{24}, \quad \frac{7}{12} = \frac{14}{24} $$ 6. Add the fractions: $$ \frac{3}{24} + \frac{14}{24} = \frac{17}{24} $$ 7. Final answer: $$ P(\text{pink or blue}) = \frac{17}{24} $$