1. **State the problem:** We are given the probabilities that Kebba, Ebou, and Omar will hit a target as $\frac{2}{3}$, $\frac{3}{4}$, and $\frac{4}{5}$ respectively. We need to find the probability that **only Kebba** hits the target. 2. **Formula and rules:** The probability that only Kebba hits the target means Kebba hits it, and both Ebou and Omar miss it. - Probability Kebba hits: $P(K) = \frac{2}{3}$ - Probability Ebou hits: $P(E) = \frac{3}{4}$, so probability Ebou misses: $1 - P(E) = 1 - \frac{3}{4} = \frac{1}{4}$ - Probability Omar hits: $P(O) = \frac{4}{5}$, so probability Omar misses: $1 - P(O) = 1 - \frac{4}{5} = \frac{1}{5}$ 3. **Calculate the probability that only Kebba hits:** $$ P(\text{only Kebba hits}) = P(K) \times (1 - P(E)) \times (1 - P(O)) = \frac{2}{3} \times \frac{1}{4} \times \frac{1}{5} $$ 4. **Simplify:** $$ = \frac{2}{3} \times \frac{1}{4} \times \frac{1}{5} = \frac{2}{60} = \frac{1}{30} $$ 5. **Final answer:** The probability that only Kebba hits the target is $\boxed{\frac{1}{30}}$.