Mean Packs 7Bf7B6
1. **State the problem:** We need to find the mean (expected value) of the random variable $X$, which represents the number of packs Rodrigo buys until he gets his favorite card.
2. **Recall the formula for the mean of a discrete random variable:**
$$\mu_X = E(X) = \sum x_i P(X = x_i)$$
where $x_i$ are the values of $X$ and $P(X = x_i)$ are their probabilities.
3. **Given values:**
- $X = 1, 2, 3$
- $P(X=1) = 0.10$
- $P(X=2) = 0.09$
- $P(X=3) = 0.81$
4. **Calculate the mean:**
$$\mu_X = 1 \times 0.10 + 2 \times 0.09 + 3 \times 0.81$$
$$= 0.10 + 0.18 + 2.43$$
$$= 2.71$$
5. **Interpretation:** On average, Rodrigo will buy about 2.71 packs to get his favorite card.
**Final answer:**
$$\mu_X = 2.71 \text{ packs}$$