1. Problem: Todd's locker combination has two numbers, each can be from 1 to 6. 2. We want the probability that Todd guesses the first number correctly and the second number incorrectly. 3. Total number of possibilities for each number is 6. 4. Probability of guessing the first number correctly: $\frac{1}{6}$ since only one correct number out of 6. 5. Probability of guessing the second number incorrectly: $\frac{5}{6}$ since 5 numbers are incorrect out of 6. 6. Since the guesses are independent, multiply probabilities: $$\frac{1}{6} \times \frac{5}{6} = \frac{5}{36}$$ 7. Final answer: $\frac{5}{36}$, which corresponds to option A.