1. **State the problem:** We have a spinner numbered 1 to 10 with equal probability for each number. We want the probability that the spinner lands on an even number every time in 9 spins. 2. **Determine the probability of landing on an even number in one spin:** The even numbers are 2, 4, 6, 8, 10, so there are 5 even numbers out of 10 total numbers. The probability of landing on an even number in one spin is $$\frac{5}{10} = 0.5$$. 3. **Calculate the probability of landing on an even number in all 9 spins:** Since each spin is independent, multiply the probability 9 times: $$P = 0.5^{9}$$ 4. **Calculate the numerical value:** $$0.5^{9} = \frac{1}{2^{9}} = \frac{1}{512} \approx 0.001953125$$ 5. **Convert to ordinary number:** The probability is approximately $$0.00195$$ (rounded to five decimal places). **Final answer:** The probability that the spinner lands on an even number every time in 9 spins is approximately $$0.00195$$.