Dice Card Probability
1. **Problem Statement:** James rolls a fair six-sided die and draws one card from 17 cards numbered 1 to 17. We are asked to solve four parts related to this experiment.
2. **(a) Number of possible outcomes:**
- The die has 6 outcomes.
- The card deck has 17 outcomes.
- Since these are independent events, total outcomes = $6 \times 17 = 102$.
3. **(b) Probability that the die roll and card draw are the same number:**
- Possible matching numbers are 1 through 6 (since die max is 6).
- For each matched number, one outcome.
- So, favorable outcomes = 6.
- Probability = $\frac{6}{102} = \frac{1}{17}$.
4. **(c) Probability both results are square numbers:**
- Square numbers on die: 1, 4 (since $1^2=1$, $2^2=4$; $3^2=9$ not on die).
- Square numbers on cards between 1 and 17: $1,4,9,16$.
- Possible matching pairs: (1,1), (4,4).
- Total favorable outcomes = $2$.
- Probability = $\frac{2}{102}= \frac{1}{51}$.
5. **(d) Probability James loses (result is 4 or less on either die or card):**
- Die outcomes $\leq 4$ = 4 outcomes.
- Card outcomes $\leq 4$ = 4 outcomes.
- Total outcomes = 102.
- Number of outcomes where die $\leq 4 = 4 \times 17 = 68$.
- Number where card $\leq 4 = 6 \times 4 = 24$.
- Double counted outcomes where both die and card $\leq 4 = 4 \times 4 = 16$.
- Use inclusion-exclusion: Favorable outcomes = $68 + 24 - 16 = 76$.
- Probability = $\frac{76}{102} = \frac{38}{51}$.
**Final answers:**
(a) 102
(b) $\frac{1}{17}$
(c) $\frac{1}{51}$
(d) $\frac{38}{51}$