1. The problem asks for the chance to get the item labeled "???" which has a probability of 0.02%. 2. To express this probability as a decimal, convert the percentage by dividing by 100: $$0.02\% = \frac{0.02}{100} = 0.0002$$ 3. Therefore, the chance to get the "???" item is $0.0002$ or $0.02\%$. 4. This means that out of 10,000 attempts, on average, you would get the "???" item 2 times. Final answer: The chance to get the "???" item is $0.02\%$ or $0.0002$ as a decimal.