1. The problem asks for the probability that a student chosen at random has either brown hair or ginger hair. 2. We are given: - Probability of brown hair = $\frac{7}{13}$ - Probability of ginger hair = $\frac{5}{26}$ 3. To find the combined probability of either brown or ginger hair, we add the two probabilities because these are mutually exclusive events. 4. First, find a common denominator for $\frac{7}{13}$ and $\frac{5}{26}$. The least common denominator is 26. 5. Convert $\frac{7}{13}$ to have denominator 26: $$\frac{7}{13} = \frac{7 \times 2}{13 \times 2} = \frac{14}{26}$$ 6. Now add the probabilities: $$\frac{14}{26} + \frac{5}{26} = \frac{19}{26}$$ 7. The probability that a randomly chosen student has either brown or ginger hair is $\frac{19}{26}$. Final answer: $\frac{19}{26}$