1. The problem asks for the probability that Mrs. Jones will have a baby who is both a boy and has blue eyes. 2. We are given: - Probability of boy, $P(\text{boy}) = \frac{1}{2}$ - Probability of blue eyes, $P(\text{blue eyes}) = \frac{1}{4}$ 3. Assuming the events "boy" and "blue eyes" are independent, the combined probability is the product of the two probabilities: $$P(\text{blue-eyed boy}) = P(\text{boy}) \times P(\text{blue eyes}) = \frac{1}{2} \times \frac{1}{4} = \frac{1}{8}$$ 4. Therefore, the probability that Mrs. Jones will have a blue-eyed boy is $\frac{1}{8}$. 5. The correct answer is (a) $\frac{1}{8}$.