1. The problem states that there are 24 bags of crisps in total. 2. We are given the probabilities of picking each flavour: Barbecue $\frac{1}{6}$, Chicken $\frac{1}{3}$, Pepper $0$, Cheese $\frac{12}{24}$. 3. To find the number of bags of each flavour, multiply the total number of bags by each probability. 4. Barbecue: $$24 \times \frac{1}{6} = 4$$ bags. 5. Chicken: $$24 \times \frac{1}{3} = 8$$ bags. 6. Pepper: $$24 \times 0 = 0$$ bags. 7. Cheese: $$24 \times \frac{12}{24} = 12$$ bags. 8. Therefore, the number of bags for each flavour is: - Barbecue: 4 - Chicken: 8 - Pepper: 0 - Cheese: 12 This matches the total of 24 bags.