Arun Winning Goal 84Cf52
1. **State the problem:** We need to find the probability that Arun scores the winning goal on a Saturday.
2. **Given information:**
- Probability Arun plays football on a Saturday: $P(F) = \frac{3}{4}$
- Probability Arun scores the winning goal given he plays football: $P(S|F) = \frac{1}{7}$
3. **Formula used:**
The probability that Arun scores the winning goal on a Saturday is the product of the probability he plays football and the probability he scores given he plays. This is given by the multiplication rule for dependent events:
$$P(S) = P(F) \times P(S|F)$$
4. **Calculate:**
$$P(S) = \frac{3}{4} \times \frac{1}{7} = \frac{3}{28}$$
5. **Interpretation:**
The probability that Arun scores the winning goal on a Saturday is $\frac{3}{28}$, which means out of 28 Saturdays, on average, Arun scores the winning goal 3 times.
**Final answer:**
$$\boxed{\frac{3}{28}}$$