Probability Transportation 65C11D
1. Given the survey data:
| Mode | Male | Female | Total |
|---------|------|--------|-------|
| Bus | 30 | 50 | 80 |
| Bicycle | 20 | 10 | 30 |
| Car | 25 | 15 | 40 |
Total students = 150
2. Probability that a randomly selected student is female:
$$P(\text{Female}) = \frac{\text{Total Female}}{\text{Total Students}} = \frac{50 + 10 + 15}{150} = \frac{75}{150} = 0.5$$
3. Probability that a randomly selected student walks to campus:
From the table, no data for walking is given, so assume zero or no students walk.
$$P(\text{Walk}) = 0$$
4. Probability that a student is male and uses a car:
$$P(\text{Male and Car}) = \frac{25}{150} = \frac{1}{6} \approx 0.1667$$