1. The problem asks for the amount of work done by a 22-kW car engine in 60 seconds, assuming 100% efficiency. 2. Power is defined as work done per unit time: $$P=\frac{W}{t}$$, where $P$ is power, $W$ is work, and $t$ is time. 3. Rearranging for work: $$W=P \times t$$. 4. Given: $P=22$ kilowatts (kW) and $t=60$ seconds (s). Convert power to watts (1 kW = 1000 W): $$22 \text{ kW} = 22 \times 1000 = 22000 \text{ W}$$. 5. Substitute values: $$W=22000 \text{ W} \times 60 \text{ s} = 1,320,000 \text{ J}$$. 6. The engine can do $1,320,000$ joules of work in 60 seconds at 100% efficiency.