1. **Problem statement:** A body of mass 2 kg floats on water. Given the density of water is 1000 kg/m^3, calculate the volume of the body immersed in water. 2. **Formula used:** When a body floats, the weight of the body equals the weight of the displaced water. This is Archimedes' principle. Weight of body = Weight of displaced water Mathematically, $mg = \rho V g$ where: - $m$ is the mass of the body (2 kg), - $g$ is acceleration due to gravity (cancels out on both sides), - $\rho$ is the density of water (1000 kg/m^3), - $V$ is the volume of the body immersed (what we want to find). 3. **Simplify the equation:** Since $g$ cancels out, $$m = \rho V$$ Rearranged to find $V$: $$V = \frac{m}{\rho}$$ 4. **Calculate the volume:** $$V = \frac{2}{1000} = 0.002 \text{ m}^3$$ 5. **Interpretation:** The volume of the body immersed in water is 0.002 cubic meters. This means the body displaces 0.002 m^3 of water to float, balancing its weight.