Vase Maximum Height
1. **Stating the problem:** Rex Things throws a vase vertically upward with an initial velocity of $26.2$ m/s. We need to determine the maximum height the vase reaches above its starting point.
2. **Relevant physics principle:** When an object is thrown upwards, its velocity decreases due to gravity until it reaches zero at the maximum height.
3. **Known values:** Initial velocity $v_0 = 26.2$ m/s, acceleration due to gravity $g = 9.8$ m/s$^2$
4. **Using the kinematic equation:**
$$ v^2 = v_0^2 - 2g h $$
where $v$ is the final velocity (0 m/s at max height), $h$ is the height gained.
5. **Plugging in values:**
$$ 0 = (26.2)^2 - 2 \times 9.8 \times h $$
6. **Solving for $h$:**
$$ 2 \times 9.8 \times h = (26.2)^2 $$
$$ h = \frac{(26.2)^2}{2 \times 9.8} $$
7. **Calculating:**
$(26.2)^2 = 686.44$
$$ h = \frac{686.44}{19.6} = 35.03 $$ m
8. **Conclusion:**
The vase rises approximately **35.03 meters** above its initial height.