Tennis Ball Bounces B0Dbdb
1. **Problem statement:** A tennis ball is dropped from a height $h_0=10$ m. Each bounce reaches 80% of the previous height. The time for a full bounce (up and down) from height $h$ is given by $$t = 2\sqrt{\frac{2h}{g}}$$ with $g=10$ m/s$^2$. We want to find how many full bounces occur within 20 seconds.
2. **Formula and explanation:** The height after the $n$-th bounce is $$h_n = h_0 \times 0.8^n$$.
The time for the $n$-th bounce is $$t_n = 2\sqrt{\frac{2h_n}{g}} = 2\sqrt{\frac{2h_0 \times 0.8^n}{10}} = 2\sqrt{\frac{2 \times 10 \times 0.8^n}{10}} = 2\sqrt{2 \times 0.8^n}$$.
3. **Simplify the time expression:**
$$t_n = 2\sqrt{2} \times (0.8)^{n/2}$$.
4. **Total time for $N$ bounces:**
$$T_N = \sum_{n=0}^{N-1} t_n = 2\sqrt{2} \sum_{n=0}^{N-1} (0.8)^{n/2}$$.
5. **Sum of geometric series:**
The sum is
$$S_N = \sum_{n=0}^{N-1} r^n$$ with $$r = (0.8)^{1/2} = \sqrt{0.8}$$.
So,
$$S_N = \frac{1 - r^N}{1 - r} = \frac{1 - (\sqrt{0.8})^N}{1 - \sqrt{0.8}}$$.
6. **Total time expression:**
$$T_N = 2\sqrt{2} \times \frac{1 - (\sqrt{0.8})^N}{1 - \sqrt{0.8}}$$.
7. **Find maximum $N$ such that $T_N \leq 20$ seconds:**
$$2\sqrt{2} \times \frac{1 - (\sqrt{0.8})^N}{1 - \sqrt{0.8}} \leq 20$$
8. **Isolate the term:**
$$\frac{1 - (\sqrt{0.8})^N}{1 - \sqrt{0.8}} \leq \frac{20}{2\sqrt{2}} = \frac{20}{2.8284} \approx 7.0711$$
9. **Multiply both sides:**
$$1 - (\sqrt{0.8})^N \leq 7.0711 (1 - \sqrt{0.8})$$
10. **Calculate denominator:**
$$1 - \sqrt{0.8} = 1 - 0.8944 = 0.1056$$
11. **Right side:**
$$7.0711 \times 0.1056 \approx 0.7467$$
12. **Inequality:**
$$1 - (\sqrt{0.8})^N \leq 0.7467 \implies (\sqrt{0.8})^N \geq 1 - 0.7467 = 0.2533$$
13. **Take natural logarithm:**
$$N \ln(\sqrt{0.8}) \geq \ln(0.2533)$$
14. **Calculate logs:**
$$\ln(\sqrt{0.8}) = \frac{1}{2} \ln(0.8) = \frac{1}{2} (-0.2231) = -0.11155$$
$$\ln(0.2533) = -1.372$$
15. **Solve for $N$:**
$$N \times (-0.11155) \geq -1.372 \implies N \leq \frac{-1.372}{-0.11155} = 12.3$$
16. **Interpretation:**
The maximum integer number of full bounces within 20 seconds is $$\boxed{12}$$.
Thus, the ball completes 12 full bounces within 20 seconds.