1. The problem asks to convert 60°C to °F. 2. The formula to convert Celsius to Fahrenheit is $$F = \frac{9}{5}C + 32$$. 3. Substitute $C=60$ into the formula: $$F = \frac{9}{5} \times 60 + 32 = 108 + 32 = 140$$ So, 60°C is equivalent to 140°F. 4. Next, convert 120°F to °C. 5. The formula to convert Fahrenheit to Celsius is $$C = \frac{5}{9}(F - 32)$$. 6. Substitute $F=120$: $$C = \frac{5}{9}(120 - 32) = \frac{5}{9} \times 88 = 48.89$$ So, 120°F is approximately 48.89°C. 7. Convert 300°K to °R. 8. The relation between Kelvin and Rankine is $$R = \frac{9}{5}K$$. 9. Substitute $K=300$: $$R = \frac{9}{5} \times 300 = 540$$ So, 300°K is equivalent to 540°R. 10. Convert 1200°R to °K. 11. Using the inverse relation $$K = \frac{5}{9}R$$. 12. Substitute $R=1200$: $$K = \frac{5}{9} \times 1200 = 666.67$$ So, 1200°R is approximately 666.67°K. 13. If the °F scale is thrice the °C scale, find the values of °F and °C. 14. Let $C = x$, then $F = 3x$. 15. Using the conversion formula $$F = \frac{9}{5}C + 32$$, substitute $F=3x$: $$3x = \frac{9}{5}x + 32$$ 16. Multiply both sides by 5: $$15x = 9x + 160$$ 17. Subtract $9x$ from both sides: $$6x = 160$$ 18. Solve for $x$: $$x = \frac{160}{6} = 26.67$$ 19. So, $C = 26.67$ and $F = 3 \times 26.67 = 80$. Final answers: 1. 60°C = 140°F 2. 120°F = 48.89°C 3. 300°K = 540°R 4. 1200°R = 666.67°K 5. If °F is thrice °C, then °C = 26.67 and °F = 80.