1. **State the problem:** A table weighing 348 pounds is supported by 4 identical legs. Each leg exerts a pressure of 12 pounds per square inch on the floor. We need to find the area of the bottom of each leg touching the floor. 2. **Understand the relationship:** Pressure is defined as force divided by area, so $$\text{Pressure} = \frac{\text{Force}}{\text{Area}}$$ 3. **Calculate the force on each leg:** Since the table's weight is evenly distributed, $$\text{Force per leg} = \frac{348}{4} = 87 \text{ pounds}$$ 4. **Use the pressure formula to find the area:** Rearranging, $$\text{Area} = \frac{\text{Force}}{\text{Pressure}} = \frac{87}{12}$$ 5. **Calculate the area:** $$\frac{87}{12} = 7.25 \text{ square inches}$$ **Final answer:** The area of the bottom of each leg touching the floor is $7.25$ square inches.