1. **Stating the problem:** We have a table showing times and corresponding average speeds. The times are 12, 9, 8, and 6 hours, and the average speeds are 60, 80, 90, and 120 respectively. 2. **Understanding the relationship:** Average speed is generally calculated as $$\text{Speed} = \frac{\text{Distance}}{\text{Time}}$$. If the distance is constant, speed and time are inversely proportional. 3. **Check if distance is constant:** Calculate distance for each pair using $$\text{Distance} = \text{Speed} \times \text{Time}$$. - For time 12 and speed 60: $$60 \times 12 = 720$$ - For time 9 and speed 80: $$80 \times 9 = 720$$ - For time 8 and speed 90: $$90 \times 8 = 720$$ - For time 6 and speed 120: $$120 \times 6 = 720$$ All distances are equal to 720, confirming constant distance. 4. **Interpreting the options:** The options A, B, C, D are fractions of hours: 1/4, 2/5, 3/2, 5/2. These might represent time intervals or durations. 5. **Summary:** The data shows that as time decreases, average speed increases to maintain the same distance of 720 units. Final answer: The distance traveled is constant at 720 units, and speed and time are inversely proportional as shown by the table.