1. **Problem statement:** We need to find the difference between the speed of the space probe as it travels towards Venus and the speed as it travels away from Venus based on the distance-time graph. 2. **Understanding the graph:** The graph shows distance from Venus (in km) on the vertical axis and time (in hours) on the horizontal axis. - The probe starts at 1400 km at 0 hours. - It travels towards Venus, reaching 500 km at 6 hours. - Then it travels away from Venus, returning to 1400 km at 16 hours. 3. **Formula for speed:** Speed is the rate of change of distance with respect to time. $$\text{Speed} = \frac{\text{Change in distance}}{\text{Change in time}}$$ 4. **Calculate speed towards Venus:** - Initial distance: 1400 km at 0 hours - Final distance: 500 km at 6 hours $$\text{Speed towards Venus} = \frac{500 - 1400}{6 - 0} = \frac{-900}{6} = -150 \text{ km/h}$$ (The negative sign indicates the probe is moving closer to Venus.) 5. **Calculate speed away from Venus:** - Initial distance: 500 km at 6 hours - Final distance: 1400 km at 16 hours $$\text{Speed away from Venus} = \frac{1400 - 500}{16 - 6} = \frac{900}{10} = 90 \text{ km/h}$$ 6. **Calculate the difference in speeds:** We take the absolute difference between the magnitudes of the speeds: $$| -150 | - 90 | = 150 - 90 = 60 \text{ km/h}$$ 7. **Final answer:** The difference between the speed towards Venus and the speed away from Venus is **60 km/h**.