1. **Problem Statement:** A ray of light travels from air (refractive index $n_1 = 1$) into crown glass (refractive index $n_2 = 1.523$) and strikes the surface at an angle of incidence $\theta_1 = 30^\circ$. We need to find the angle of refraction $\theta_2$ inside the crown glass. 2. **Formula Used:** Snell's Law relates the angles and refractive indices: $$n_1 \sin \theta_1 = n_2 \sin \theta_2$$ 3. **Explanation:** - $n_1$ and $n_2$ are the refractive indices of the first and second medium respectively. - $\theta_1$ is the angle of incidence. - $\theta_2$ is the angle of refraction. 4. **Calculation:** Substitute the known values: $$1 \times \sin 30^\circ = 1.523 \times \sin \theta_2$$ Since $\sin 30^\circ = 0.5$, we have: $$0.5 = 1.523 \sin \theta_2$$ 5. **Solve for $\sin \theta_2$:** $$\sin \theta_2 = \frac{0.5}{1.523} \approx 0.3285$$ 6. **Find $\theta_2$:** $$\theta_2 = \arcsin(0.3285) \approx 19.2^\circ$$ **Final Answer:** The angle of refraction inside the crown glass is approximately $19.2^\circ$.