Pressure Depth Cef8Ca
1. **Problem Statement:**
We are given two points representing depth and pressure: (4, 140) and (10, 200). We need to find the linear equation relating pressure $P$ to depth $d$, and answer related questions.
2. **Formula and Rules:**
The equation of a line is $P = md + b$, where $m$ is the slope and $b$ is the pressure intercept (pressure at depth 0).
3. **Calculate the slope $m$:**
$$m = \frac{P_2 - P_1}{d_2 - d_1} = \frac{200 - 140}{10 - 4} = \frac{60}{6} = 10$$
4. **Find the intercept $b$:**
Using point (4, 140):
$$140 = 10 \times 4 + b \implies b = 140 - 40 = 100$$
5. **Equation of the line:**
$$P = 10d + 100$$
6. **Interpret $b$ (pressure intercept):**
The intercept $b = 100$ kPa represents the pressure at the surface (depth 0 metres).
7. **Find depth when pressure is 245 kPa:**
$$245 = 10d + 100 \implies 10d = 145 \implies d = 14.5$$ metres
8. **Find pressure at depth 17 metres:**
$$P = 10 \times 17 + 100 = 170 + 100 = 270$$ kPa
9. **Interpret slope $m$:**
The slope $m = 10$ kPa/m means pressure increases by 10 kPa for every 1 metre increase in depth.
**Final answers:**
- Equation: $P = 10d + 100$
- Pressure intercept: 100 kPa (pressure at surface)
- Depth at 245 kPa: 14.5 metres
- Pressure at 17 metres: 270 kPa
- Slope: 10 kPa/m (rate of pressure increase with depth)