Newtons Cooling
1. **State the problem:** A thermometer starts at 21 degrees indoors and is taken outside to -7 degrees. After 1 minute, it reads 14 degrees. We need to find the temperature reading after $t$ minutes.
2. **Model the problem:** This is a Newton's Law of Cooling problem, which states temperature $T(t)$ changes according to $$\frac{dT}{dt} = -k(T - T_\text{env})$$ where $T_\text{env} = -7$ degrees is the environment temperature.
3. **General solution:** The solution is $$T(t) = T_\text{env} + (T_0 - T_\text{env}) e^{-kt}$$ with initial temperature $T_0 = 21$.
4. **Use given data to find $k$:** At $t=1$, $$14 = -7 + (21 + 7) e^{-k}\Rightarrow 14 = -7 + 28 e^{-k}$$
5. **Solve for $k$:**
$$14 + 7 = 28 e^{-k}$$
$$21 = 28 e^{-k}$$
$$e^{-k} = \frac{21}{28} = \frac{3}{4}$$
$$-k = \ln\frac{3}{4}$$
$$k = -\ln\frac{3}{4} = \ln\frac{4}{3}$$
6. **Find $T(t)$:**
$$T(t) = -7 + 28 e^{-kt} = -7 + 28 \left(e^{-k}\right)^t = -7 + 28 \left(\frac{3}{4}\right)^t$$
7. **Final temperature reading after $t$ minutes:** $$\boxed{T(t) = -7 + 28 \left(\frac{3}{4}\right)^t}$$
This formula lets you calculate the temperature at any time $t$ after being taken outdoors.