1. **Problem Statement:** An effort of 20 N is applied to lift a load of 120 N using a machine. The effort moves through a distance of 50 m, and the load moves through a distance of 200 m. We need to calculate the efficiency of the machine and the velocity ratio. 2. **Formulas and Definitions:** - Mechanical Advantage (MA) = Load / Effort - Velocity Ratio (VR) = Distance moved by Effort / Distance moved by Load - Efficiency (\(\eta\)) = (Mechanical Advantage / Velocity Ratio) \times 100% 3. **Calculate Mechanical Advantage:** $$MA = \frac{120}{20} = 6$$ 4. **Calculate Velocity Ratio:** $$VR = \frac{50}{200} = 0.25$$ 5. **Calculate Efficiency:** $$\eta = \frac{MA}{VR} \times 100 = \frac{6}{0.25} \times 100 = 2400\%$$ 6. **Interpretation:** The efficiency calculated is 2400%, which is not physically possible as efficiency cannot exceed 100%. This suggests an error in the problem data or interpretation. Usually, the effort distance is greater than the load distance, so please verify the distances given. **Final answers:** - Velocity Ratio = 0.25 - Efficiency = 2400% (likely an error in input data)