1. The problem states that light intensity $I$ is inversely proportional to the square of the distance $d$, given by the formula: $$I = \frac{1}{d^2}$$ 2. We are given a specific intensity value $I = 0.06$ and asked to find the distance $d$. 3. Rearranging the formula to solve for $d$, we get: $$d^2 = \frac{1}{I}$$ 4. Substitute $I = 0.06$ into the equation: $$d^2 = \frac{1}{0.06}$$ 5. Calculate the right side: $$d^2 = 16.6667$$ 6. Take the square root of both sides to find $d$: $$d = \sqrt{16.6667}$$ 7. Calculate the square root: $$d \approx 4.08$$ 8. Therefore, the distance corresponding to the light intensity of 0.06 is approximately 4.08 units.