1. The problem states that light intensity is given by the formula $$\text{Light intensity} = \frac{1}{\text{distance}^2}$$ and the distance is given as $$\text{distance} = \frac{1}{\sqrt{0.85}}$$. 2. First, calculate the distance: $$\text{distance} = \frac{1}{\sqrt{0.85}} = \frac{1}{0.921954445} \approx 1.084\,.$$ 3. Next, substitute this distance into the light intensity formula: $$\text{Light intensity} = \frac{1}{(1.084)^2} = \frac{1}{1.175} \approx 0.851\,.$$ 4. Therefore, the light intensity is approximately $$0.851$$ when the distance is $$\frac{1}{\sqrt{0.85}}$$.