Kinetic Energy 663C52
1. **State the problem:**
(a)(i) Define internal energy.
(a)(ii) State the kinetic theory assumption leading to zero potential energy between ideal gas molecules.
(b) Use the equation $pV = \frac{1}{3} Nm\langle c^2 \rangle$ to show that the mean kinetic energy $\langle E_k \rangle$ of a molecule is $\frac{3}{2} kT$.
2. **Definitions and assumptions:**
- Internal energy is the total energy contained within a system due to the kinetic and potential energies of its molecules.
- The kinetic theory assumption is that ideal gas molecules have no intermolecular forces, so potential energy between molecules is zero.
3. **Derivation:**
Given:
$$pV = \frac{1}{3} Nm \langle c^2 \rangle$$
where:
- $p$ = pressure
- $V$ = volume
- $N$ = number of molecules
- $m$ = mass of one molecule
- $\langle c^2 \rangle$ = mean square speed of molecules
From the ideal gas law:
$$pV = NkT$$
where $k$ is Boltzmann constant and $T$ is temperature.
Equate the two expressions for $pV$:
$$NkT = \frac{1}{3} Nm \langle c^2 \rangle$$
Divide both sides by $N$:
$$kT = \frac{1}{3} m \langle c^2 \rangle$$
Multiply both sides by $\frac{3}{2}$:
$$\frac{3}{2} kT = \frac{1}{2} m \langle c^2 \rangle$$
Note that the mean kinetic energy per molecule is:
$$\langle E_k \rangle = \frac{1}{2} m \langle c^2 \rangle$$
Therefore:
$$\langle E_k \rangle = \frac{3}{2} kT$$
4. **Explanation:**
- The internal energy includes kinetic energy of molecules.
- The assumption of no intermolecular forces means potential energy is zero.
- Using the kinetic theory relation and ideal gas law, we relate pressure, volume, and temperature to molecular speeds.
- This leads to the expression for mean kinetic energy in terms of temperature and Boltzmann constant.
**Final answer:**
$$\boxed{\langle E_k \rangle = \frac{3}{2} kT}$$