Interception Time F12544
1. **State the problem:**
We have a target approaching at 240 km/h and an interceptor traveling at 840 km/s. They are initially 14,000 meters apart. We need to find how long it will take for the interceptor to catch the target.
2. **Convert units to be consistent:**
- Target speed: 240 km/h = $\frac{240 \times 1000}{3600} = 66.67$ m/s
- Interceptor speed: 840 km/s = $840 \times 1000 = 840,000$ m/s
3. **Relative speed:**
Since both are moving towards each other, the relative speed is the sum of their speeds:
$$v_{relative} = 66.67 + 840,000 = 840,066.67 \text{ m/s}$$
4. **Time to intercept:**
Using the formula $\text{time} = \frac{\text{distance}}{\text{speed}}$:
$$t = \frac{14,000}{840,066.67} \approx 0.01667 \text{ seconds}$$
5. **Conclusion:**
The interceptor will catch the target in approximately 0.01667 seconds.