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Interception Time F12544

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Interception Time F12544


1. **State the problem:** We have a target approaching at 240 km/h and an interceptor traveling at 840 km/s. They are initially 14,000 meters apart. We need to find how long it will take for the interceptor to catch the target. 2. **Convert units to be consistent:** - Target speed: 240 km/h = $\frac{240 \times 1000}{3600} = 66.67$ m/s - Interceptor speed: 840 km/s = $840 \times 1000 = 840,000$ m/s 3. **Relative speed:** Since both are moving towards each other, the relative speed is the sum of their speeds: $$v_{relative} = 66.67 + 840,000 = 840,066.67 \text{ m/s}$$ 4. **Time to intercept:** Using the formula $\text{time} = \frac{\text{distance}}{\text{speed}}$: $$t = \frac{14,000}{840,066.67} \approx 0.01667 \text{ seconds}$$ 5. **Conclusion:** The interceptor will catch the target in approximately 0.01667 seconds.