1. **State the problem:** A Bell 222 helicopter with mass 3560 kg is hovering 17 m above the ground. When the engine fails, we want to find the impact velocity when it hits the ground, in m/s. 2. **Identify the type of motion:** This is a free fall problem under gravity with initial velocity $u=0$ (hovering means zero initial vertical speed). 3. **Known values:** - Height $h=17$ m - Acceleration due to gravity $g=9.8$ m/s$^2$ - Initial velocity $u=0$ m/s 4. **Use the kinematic equation:** $$v^2 = u^2 + 2gh$$ where $v$ is the final velocity (impact velocity). 5. **Substitute values:** $$v^2 = 0^2 + 2 \times 9.8 \times 17 = 333.2$$ 6. **Calculate $v$:** $$v = \sqrt{333.2} \approx 18.25 \text{ m/s}$$ 7. **Answer:** The helicopter's impact velocity when it hits the ground is approximately **18.25 m/s**.