1. **State the problem:** We are given a filament lamp with a voltage rating of $240$ V and a resistance of $960$ ohms. We need to find the current taken by the lamp and its power rating. 2. **Find the current taken by the lamp:** Use Ohm's law, which states that current $I$ is voltage $V$ divided by resistance $R$. $$I = \frac{V}{R}$$ Substituting the values: $$I = \frac{240}{960} = 0.25 \text{ A}$$ So, the current taken by the lamp is $0.25$ amperes. 3. **Find the power rating of the lamp:** Power $P$ can be calculated using the formula: $$P = \frac{V^2}{R}$$ Substitute the values: $$P = \frac{240^2}{960} = \frac{57600}{960} = 60 \text{ watts}$$ So, the power rating of the lamp is $60$ watts. **Final answers:** - Current taken $I = 0.25$ A - Power rating $P = 60$ watts