Falling Distance
1. **State the problem:**
We know that the distance $d$ a marble falls is directly proportional to the square of the time $t$ it has been falling. Given that it falls 42.3 metres in 3 seconds, we want to find how far it falls in 5 seconds.
2. **Write the formula for direct proportionality:**
Since $d$ is directly proportional to $t^2$, we write:
$$ d = k t^2 $$
where $k$ is the constant of proportionality.
3. **Find the constant $k$ using the given data:**
Given $d = 42.3$ metres when $t = 3$ seconds, substitute these values:
$$ 42.3 = k \times 3^2 $$
$$ 42.3 = 9k $$
Solve for $k$:
$$ k = \frac{42.3}{9} = 4.7 $$
4. **Use $k$ to find the distance fallen in 5 seconds:**
Substitute $t = 5$ and $k = 4.7$ into the formula:
$$ d = 4.7 \times 5^2 = 4.7 \times 25 = 117.5 $$
5. **Final answer:**
The marble falls **117.5 metres** in 5 seconds.
This method uses the rule of direct proportionality and substitution to find the unknown distance.