1. The problem is to calculate the energy released per kilogram (J/kg) by a system where the fall height difference is 800 m and the specific heat capacity is 4200 J/kg °C. 2. Given that the energy released per kilogram is calculated by multiplying the specific heat capacity by the temperature change: $$E = c \times \Delta T$$ 3. We do not have the temperature change \(\Delta T\) directly, but since the full question image is not visible, I will assume the temperature change is the result of the potential energy due to the fall converted into heat. 4. The potential energy per kilogram is given by: $$PE = g \times h = 9.81 \times 800 = 7848 \text{ J/kg}$$ 5. If we consider this energy converts fully into heat raising water temperature, then temperature change is: $$\Delta T = \frac{PE}{c} = \frac{7848}{4200} \approx 1.87 ^\circ C$$ 6. Therefore, the energy released per kilogram is $$E = 4200 \times 1.87 = 7848 \text{ J/kg}$$ which matches the potential energy calculation. 7. Hence, the energy released per kilogram by the system is 7848 J/kg.