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Distance Displacement Cc183E

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Distance Displacement Cc183E


1. **State the problem:** An object starts at position 0 on the number line, moves 2 units to the right, then 4 units to the left. We need to find the total distance traveled and the displacement. 2. **Formulas and definitions:** - Distance traveled is the total length of the path covered, regardless of direction. - Displacement is the difference between the final position and the initial position, considering direction. 3. **Calculate distance traveled:** - First move: 2 units to the right. - Second move: 4 units to the left. - Total distance = $2 + 4 = 6$ units. 4. **Calculate displacement:** - Initial position = 0. - After first move: position = $0 + 2 = 2$. - After second move: position = $2 - 4 = -2$. - Displacement = final position $- $ initial position $= -2 - 0 = -2$ units. 5. **Interpretation:** - Distance traveled is always positive: 6 units. - Displacement is $-2$ units, meaning 2 units to the left from the start. **Final answers:** - Distance traveled = 6 units. - Displacement = $-2$ units.