1. **State the problem:** An object starts at position 0 on the number line, moves 2 units to the right, then 4 units to the left. We need to find the total distance traveled and the displacement. 2. **Formulas and definitions:** - Distance is the total length of the path traveled, ignoring direction. - Displacement is the net change in position, considering direction, calculated as $$\text{Displacement} = \text{Final Position} - \text{Initial Position}$$. 3. **Calculate distance:** - The object moves 2 units right: distance = 2 units. - Then moves 4 units left: distance = 4 units. - Total distance traveled = $$2 + 4 = 6$$ units. 4. **Calculate displacement:** - Initial position = 0. - After moving right 2 units, position = $$0 + 2 = 2$$. - After moving left 4 units, position = $$2 - 4 = -2$$. - Displacement = Final position - Initial position = $$-2 - 0 = -2$$ units. - The displacement magnitude is 2 units to the left. **Final answers:** - Distance traveled = 6 units. - Displacement = -2 units (2 units to the left).