1. **State the problem:** Khalid drives from home to a hotel with a displacement–time graph given. We need to find: a) The displacement of the hotel from Khalid's home. b) Khalid's average velocity for the whole journey. 2. **Analyze the graph:** - The graph shows displacement (km) vs. time (hours). - From 0 to 2 hours, displacement increases linearly to about 30 km. - From 2 to 3 hours, displacement remains constant at 30 km (Khalid stops for lunch). - From 3 to 5 hours, displacement increases again to about 45 km. 3. **Determine the scale on the vertical axis:** - The problem states each vertical unit corresponds to 15 km. - The graph shows displacement at 2 hours is 30 km, so the scale is consistent. 4. **Calculate the total displacement of the hotel from home:** - Final displacement at 5 hours is 45 km. - Therefore, the hotel is 45 km from Khalid's home. 5. **Calculate Khalid's average velocity for the whole journey:** - Total displacement: $45$ km. - Total time: $5$ hours. - Average velocity $= \frac{\text{total displacement}}{\text{total time}} = \frac{45}{5} = 9$ km/h. **Final answers:** - a) Displacement of the hotel from home is $45$ km. - b) Average velocity for the whole journey is $9$ km/h.