1. **State the problem:** We want to find the density of lead in SI units (kg/m\(^3\)) given the mass \( m = 23.94 \) g and the volume \( V = 2.10 \) cm\(^3\). 2. **Convert the mass to kilograms:** Since 1 g = 0.001 kg, \[ m = 23.94 \times 0.001 = 0.02394 \text{ kg} \] 3. **Convert the volume to cubic meters:** Given 1 cm = 0.01 m, thus 1 cm\(^3\) = (0.01 m)\(^3\) = \(1 \times 10^{-6}\) m\(^3\). So, \[ V = 2.10 \times 10^{-6} \text{ m}^3 \] 4. **Calculate density using the formula:** \[ \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{0.02394}{2.10 \times 10^{-6}} \] 5. **Perform the division:** \[ \text{Density} = \frac{0.02394}{0.0000021} = 11400 \text{ kg/m}^3 \] **Final answer:** The density of lead is \( 1.14 \times 10^{4} \) kg/m\(^3\).