Density Copper
1. **State the problem:**
We have a sculpture made of two parts: a cuboid and a square-based pyramid on top. Both have bases of side 3 cm.
2. **Given data:**
- Side of base (cuboid and pyramid): $3$ cm
- Height of cuboid: $8$ cm
- Total height of sculpture: $15$ cm
- Total mass of sculpture: $738$ g
- Density of iron (cuboid): $7.8$ g/cm$^3$
- Density of copper (pyramid): unknown, to be found
3. **Calculate the height of the pyramid:**
$$\text{Height of pyramid} = 15 - 8 = 7 \text{ cm}$$
4. **Calculate the volume of the cuboid:**
$$\text{Volume}_{cuboid} = \text{base area} \times \text{height} = 3 \times 3 \times 8 = 72 \text{ cm}^3$$
5. **Calculate the volume of the pyramid:**
$$\text{Volume}_{pyramid} = \frac{1}{3} \times \text{base area} \times \text{height} = \frac{1}{3} \times 3 \times 3 \times 7 = \frac{1}{3} \times 9 \times 7 = 21 \text{ cm}^3$$
6. **Calculate the mass of the cuboid:**
$$\text{Mass}_{cuboid} = \text{density} \times \text{volume} = 7.8 \times 72 = 561.6 \text{ g}$$
7. **Calculate the mass of the pyramid:**
$$\text{Mass}_{pyramid} = \text{total mass} - \text{mass}_{cuboid} = 738 - 561.6 = 176.4 \text{ g}$$
8. **Calculate the density of copper (pyramid):**
$$\text{Density}_{copper} = \frac{\text{mass}_{pyramid}}{\text{volume}_{pyramid}} = \frac{176.4}{21} = 8.4 \text{ g/cm}^3$$
**Final answer:** The density of the copper is $8.4$ g/cm$^3$.