1. **Problem statement:** Given a circuit with resistors $R_1 > R_2 > R_3 > R_4$ arranged such that $R_1$ and $R_4$ are in series with the voltage source, and $R_2$ and $R_3$ are in parallel between them, determine the relationship between the currents $I_1, I_2, I_3, I_4$ through each resistor. 2. **Analyze the circuit:** Since $R_1$ and $R_4$ are in series, the current through them is the same: $$I_1 = I_4.$$ 3. **Parallel branch currents:** The current splits between $R_2$ and $R_3$ in parallel. The current through a resistor in parallel is inversely proportional to its resistance, so the smaller the resistance, the larger the current. 4. **Given resistances:** $R_1 > R_2 > R_3 > R_4$ means: - $R_1$ is the largest resistance. - $R_4$ is the smallest resistance. - $R_2$ and $R_3$ are in between, with $R_2 > R_3$. 5. **Current through parallel resistors:** Since $R_3 < R_2$, the current through $R_3$ is greater than through $R_2$: $$I_3 > I_2.$$ 6. **Current through series resistors:** The current $I_1 = I_4$ is the total current entering the parallel branch, so it must be greater than the current through either branch resistor: $$I_1 = I_4 > I_3 > I_2.$$ 7. **Conclusion:** The correct relationship is $$I_1 = I_4 > I_3 > I_2,$$ which corresponds to answer choice A.