1. **State the problem:** We are given the equation $$l\varepsilon = \frac{q}{6 \times 10^{18}} = 1.6 \times 10^{-19} q$$ and need to understand or verify the relationship. 2. **Analyze the equation:** The equation shows two expressions for $$l\varepsilon$$ involving $$q$$. 3. **Compare the two expressions:** $$\frac{q}{6 \times 10^{18}} = 1.6 \times 10^{-19} q$$ 4. **Simplify the left side:** $$\frac{q}{6 \times 10^{18}} = q \times \frac{1}{6 \times 10^{18}}$$ 5. **Evaluate the numerical value:** $$\frac{1}{6 \times 10^{18}} = \frac{1}{6} \times 10^{-18} \approx 0.1667 \times 10^{-18} = 1.667 \times 10^{-19}$$ 6. **Compare with the right side coefficient:** $$1.6 \times 10^{-19}$$ is approximately equal to $$1.667 \times 10^{-19}$$, showing the two expressions are nearly equal. 7. **Conclusion:** The equation expresses $$l\varepsilon$$ as proportional to $$q$$ with a constant factor close to $$1.6 \times 10^{-19}$$, which matches the approximate value of $$\frac{1}{6 \times 10^{18}}$$. **Final answer:** $$l\varepsilon = 1.6 \times 10^{-19} q$$