1. **Problem Statement:** Find the center of mass of four 2 kg bodies placed at each corner of a square of side 1.5 m. 2. **Formula:** The center of mass $(x_{cm}, y_{cm})$ for discrete masses is given by: $$x_{cm} = \frac{\sum m_i x_i}{\sum m_i}, \quad y_{cm} = \frac{\sum m_i y_i}{\sum m_i}$$ where $m_i$ are the masses and $(x_i, y_i)$ their coordinates. 3. **Given Data:** - Mass of each body $m = 2$ kg - Square side length $= 1.5$ m - Coordinates of masses: - Mass 1 at $(0,0)$ - Mass 2 at $(1.5,0)$ - Mass 3 at $(0,1.5)$ - Mass 4 at $(1.5,1.5)$ 4. **Calculate total mass:** $$M = 4 \times 2 = 8 \text{ kg}$$ 5. **Calculate $x_{cm}$:** $$x_{cm} = \frac{2 \times 0 + 2 \times 1.5 + 2 \times 0 + 2 \times 1.5}{8} = \frac{0 + 3 + 0 + 3}{8} = \frac{6}{8} = 0.75 \text{ m}$$ 6. **Calculate $y_{cm}$:** $$y_{cm} = \frac{2 \times 0 + 2 \times 0 + 2 \times 1.5 + 2 \times 1.5}{8} = \frac{0 + 0 + 3 + 3}{8} = \frac{6}{8} = 0.75 \text{ m}$$ 7. **Interpretation:** The center of mass is at the midpoint of the square, coordinates $(0.75, 0.75)$ meters. **Final answer:** The center of mass of the four 2 kg bodies is at $$\boxed{(0.75, 0.75) \text{ meters}}$$.