1. **Problem:** Calculate the average power required for a 1200-kg car to accelerate from rest to 25 m/s in 8.0 s, ignoring friction losses. 2. **Formula:** Power is the rate of doing work, and work done here is the change in kinetic energy. $$P_{avg} = \frac{W}{t} = \frac{\Delta KE}{t} = \frac{\frac{1}{2} m v^2 - 0}{t}$$ where $m=1200$ kg, $v=25$ m/s, and $t=8.0$ s. 3. **Calculate kinetic energy:** $$KE = \frac{1}{2} \times 1200 \times 25^2 = 0.5 \times 1200 \times 625 = 375000 \text{ J}$$ 4. **Calculate average power:** $$P_{avg} = \frac{375000}{8.0} = 46875 \text{ W}$$ 5. **Answer:** The motor must produce an average power of **46875 W** or **46.875 kW** to cause this acceleration.