1. **Problem:** Asha drives 45 km north, then 15 km east. Find the total distance covered and displacement. 2. **Distance formula:** Distance is the total length traveled, so add all segments: $45 + 15 = 60$ km. 3. **Displacement formula:** Displacement is the straight-line distance from start to end, calculated using Pythagoras' theorem for perpendicular directions: $$\text{displacement} = \sqrt{45^2 + 15^2}$$ 4. **Calculate displacement:** $$\sqrt{45^2 + 15^2} = \sqrt{2025 + 225} = \sqrt{2250} = 15\sqrt{10} \approx 47.43 \text{ km}$$ 5. **Direction of displacement:** The angle north of east is: $$\theta = \tan^{-1}\left(\frac{45}{15}\right) = \tan^{-1}(3) \approx 71.57^\circ \text{ north of east}$$ 6. **Answer:** - Distance covered: 60 km - Displacement: approximately 47.43 km at $71.57^\circ$ north of east This means Asha traveled a total of 60 km but her straight-line distance from start to finish is about 47.43 km in the direction 71.57 degrees north of east.