1. **Problem Statement:** Calculate the resistance $R$ of a 1000 m long aluminum cable with a circumference $C=0.015$ m and aluminum resistivity $\rho=2.82 \times 10^{-8}$ $\Omega m$. 2. **Find the radius $r$ of the cable:** Given circumference formula: $$ C = 2 \pi r $$ Rearranging to find radius: $$ r = \frac{C}{2 \pi} = \frac{0.015}{2 \times 3.14} \approx 0.0024 \text{ m} $$ 3. **Calculate cross-sectional area $A$: ** $$ A = \pi r^2 = 3.14 \times (0.0024)^2 = 3.14 \times 5.76 \times 10^{-6} \approx 1.811 \times 10^{-5} \text{ m}^2 $$ 4. **Calculate resistance $R$ using the formula:** $$ R = \frac{\rho L}{A} = \frac{2.82 \times 10^{-8} \times 1000}{1.811 \times 10^{-5}} $$ Calculate numerator: $$ 2.82 \times 10^{-8} \times 1000 = 2.82 \times 10^{-5} $$ Calculate resistance: $$ R = \frac{2.82 \times 10^{-5}}{1.811 \times 10^{-5}} \approx 1.56 \ \Omega $$ **Final Answer:** The resistance of the aluminum cable is approximately $1.56 \ \Omega$.