1. **State the problem:** The sale price of a bag is 1080 rupees after a 20% reduction from the normal price. We need to find the normal price. 2. **Formula and explanation:** When a price is reduced by a percentage, the sale price is given by: $$\text{Sale Price} = \text{Normal Price} \times (1 - \text{Reduction Percentage})$$ Here, the reduction percentage is 20%, so: $$\text{Sale Price} = \text{Normal Price} \times (1 - 0.20) = \text{Normal Price} \times 0.80$$ 3. **Set up the equation:** Let the normal price be $x$ rupees. $$1080 = x \times 0.80$$ 4. **Solve for $x$:** $$x = \frac{1080}{0.80}$$ $$x = 1350$$ 5. **Interpretation:** The normal price of the bag before the sale was 1350 rupees. **Final answer:** 1350 rupees