Pde Separation B67C76
1. **Problem Statement:**
We are given the partial differential equation (PDE) in spherical coordinates:
$$\frac{\partial u}{\partial t} = \frac{1}{r^2} \frac{\partial}{\partial r} \left(r^2 \frac{\partial u}{\partial r}\right) + \frac{1}{r^2 \sin \phi} \frac{\partial}{\partial \phi} \left(\sin \phi \frac{\partial u}{\partial \phi}\right) + \frac{1}{r^2 \sin^2 \phi} \frac{\partial^2 u}{\partial \theta^2} + k$$
with boundary conditions (BC):
$$u(R, \theta, \phi, t) = 0$$
$$\frac{\partial u}{\partial \theta}(r, 0, \phi, t) = \frac{\partial u}{\partial \theta}(r, \frac{\pi}{2}, \phi, t) = 0$$
$$\frac{\partial u}{\partial \phi}(r, \theta, 0, t) = \frac{\partial u}{\partial \phi}(r, \theta, \pi, t) = 0$$
and initial condition (IC):
$$u(r, \theta, \phi, 0) = \beta(r, \theta, \phi)$$
2. **Method: Separation of Variables**
We assume a solution of the form:
$$u(r, \theta, \phi, t) = R(r) \Theta(\theta) \Phi(\phi) T(t)$$
3. **Substitute into PDE:**
Substitute $u$ into the PDE and divide both sides by $R \Theta \Phi T$ to separate variables.
4. **Separate time variable:**
We get an equation of the form:
$$\frac{1}{T} \frac{dT}{dt} = \text{spatial terms} + k$$
Set the time-dependent part equal to a separation constant $-\lambda$:
$$\frac{1}{T} \frac{dT}{dt} = -\lambda$$
which solves to:
$$T(t) = T_0 e^{-\lambda t}$$
5. **Spatial part:**
The spatial part satisfies:
$$\frac{1}{r^2 R} \frac{d}{dr} \left(r^2 \frac{dR}{dr}\right) + \frac{1}{r^2 \sin \phi \Theta \Phi} \frac{\partial}{\partial \phi} \left(\sin \phi \frac{\partial (\Theta \Phi)}{\partial \phi}\right) + \frac{1}{r^2 \sin^2 \phi \Theta \Phi} \frac{\partial^2 (\Theta \Phi)}{\partial \theta^2} + k = -\lambda$$
6. **Angular separation:**
Separate $\theta$ and $\phi$ variables by assuming:
$$\Theta(\theta)$$ and $$\Phi(\phi)$$ satisfy eigenvalue problems with boundary conditions:
- $\frac{d\Theta}{d\theta}(0) = \frac{d\Theta}{d\theta}(\frac{\pi}{2}) = 0$
- $\frac{d\Phi}{d\phi}(0) = \frac{d\Phi}{d\phi}(\pi) = 0$
7. **Radial equation:**
The radial part satisfies:
$$\frac{1}{r^2} \frac{d}{dr} \left(r^2 \frac{dR}{dr}\right) + \left(\lambda - k - \frac{\mu}{r^2}\right) R = 0$$
where $\mu$ is the separation constant from angular parts.
8. **Boundary condition for $R$:**
$$R(R) = 0$$
9. **Summary:**
- Solve angular eigenvalue problems for $\Theta$ and $\Phi$ with given Neumann BCs.
- Use eigenvalues to solve radial ODE with Dirichlet BC.
- Time dependence is exponential decay with rate $\lambda$.
- Initial condition $u(r, \theta, \phi, 0) = \beta(r, \theta, \phi)$ determines coefficients in series expansion.
This method fully separates variables and reduces the PDE to ODEs solvable by standard techniques.
**Final answer:** The solution is expressed as a series:
$$u(r, \theta, \phi, t) = \sum_{n,m,l} A_{nml} R_n(r) \Theta_m(\theta) \Phi_l(\phi) e^{-\lambda_{nml} t}$$
where $A_{nml}$ are coefficients from initial condition expansion.