Membrane Deflection C2Ec6C
1. **Problem Statement:**
Find the deflection $u(x,y,t)$ of a rectangular membrane with sides $a$ and $b$, wave speed $c=1$, initial displacement $f(x,y) = \sin\left(\frac{6\pi x}{a}\right) \sin\left(\frac{2\pi y}{b}\right)$, and initial velocity zero.
2. **Governing Equation:**
The membrane vibration satisfies the 2D wave equation:
$$\frac{\partial^2 u}{\partial t^2} = c^2 \left(\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2}\right)$$
with boundary conditions $u=0$ on edges $x=0,a$ and $y=0,b$.
3. **Separation of Variables and Eigenmodes:**
The solution can be expressed as a sum of eigenmodes:
$$u(x,y,t) = \sum_{m=1}^\infty \sum_{n=1}^\infty A_{mn} \cos(c \pi t \sqrt{(m/a)^2 + (n/b)^2}) \sin\left(\frac{m \pi x}{a}\right) \sin\left(\frac{n \pi y}{b}\right)$$
4. **Initial Conditions:**
- Initial displacement: $u(x,y,0) = f(x,y) = \sin\left(\frac{6\pi x}{a}\right) \sin\left(\frac{2\pi y}{b}\right)$
- Initial velocity: $\frac{\partial u}{\partial t}(x,y,0) = 0$
5. **Determining Coefficients:**
Since initial velocity is zero, the time-dependent part is cosine only.
The initial displacement matches exactly one eigenmode with $m=6$, $n=2$.
Thus, all $A_{mn} = 0$ except $A_{6,2}$.
6. **Coefficient $A_{6,2}$:**
Using orthogonality of sine functions,
$$A_{6,2} = \frac{4}{ab} \int_0^a \int_0^b f(x,y) \sin\left(\frac{6\pi x}{a}\right) \sin\left(\frac{2\pi y}{b}\right) dy dx = 1$$
7. **Final Solution:**
$$u(x,y,t) = \cos\left(\pi t \sqrt{\left(\frac{6}{a}\right)^2 + \left(\frac{2}{b}\right)^2}\right) \sin\left(\frac{6\pi x}{a}\right) \sin\left(\frac{2\pi y}{b}\right)$$
This represents the membrane vibrating in the $(6,2)$ mode with frequency $\omega = \pi \sqrt{(6/a)^2 + (2/b)^2}$.
**Summary:** The deflection is a single mode oscillation with the given initial shape and zero initial velocity.