1. **Stating the problem:** We need to determine which of the given numbers is a multiple of 45. 2. **Formula and rules:** A number is a multiple of 45 if it is divisible by both 9 and 5. - Divisible by 5: The number ends in 0 or 5. - Divisible by 9: The sum of the digits is divisible by 9. 3. **Check each number:** - 1827355 ends with 5 (divisible by 5). Sum of digits: 1+8+2+7+3+5+5=31 (not divisible by 9). - 8764530 ends with 0 (divisible by 5). Sum of digits: 8+7+6+4+5+3+0=33 (divisible by 9 since 33/9=3.666, no, so not divisible). - 2786115 ends with 5 (divisible by 5). Sum of digits: 2+7+8+6+1+1+5=30 (not divisible by 9). - 5841270 ends with 0 (divisible by 5). Sum of digits: 5+8+4+1+2+7+0=27 (divisible by 9 since 27/9=3). - 6347955 ends with 5 (divisible by 5). Sum of digits: 6+3+4+7+9+5+5=39 (not divisible by 9). 4. **Conclusion:** Only 5841270 is divisible by both 5 and 9, so it is a multiple of 45. **Final answer:** 5841270 is a multiple of 45.