Subjects number theory

Modular Congruence 11984F

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Modular Congruence 11984F


1. **State the problem:** Solve the congruence equation $$x \equiv 1694 \pmod{1716}$$. 2. **Understand the problem:** The congruence means that $x$ and $1694$ leave the same remainder when divided by $1716$. 3. **Simplify the congruence:** Since $1694$ is greater than $1716$, we can reduce $1694$ modulo $1716$ by subtracting $1716$: $$1694 - 1716 = -22$$ 4. **Rewrite the congruence:** $$x \equiv -22 \pmod{1716}$$ 5. **Express the remainder as a positive number:** Since remainders are usually taken as non-negative, add $1716$ to $-22$: $$-22 + 1716 = 1694$$ 6. **Final solution:** The solution to the congruence is $$x \equiv 1694 \pmod{1716}$$ which means $x$ can be any integer of the form $$x = 1694 + 1716k$$ where $k$ is any integer. **Summary:** The congruence is already simplified, and the solution set is all integers congruent to $1694$ modulo $1716$.