Hex Division
1. **Problem Statement:** Divide the hexadecimal number $\text{(13AF9)}_{16}$ by $\text{(9A)}_{16}$ and find the quotient and remainder.
2. **Convert divisor to decimal:**
$$\text{(9A)}_{16} = 9 \times 16^1 + A \times 16^0 = 9 \times 16 + 10 = 144 + 10 = 154_{10}$$
3. **Convert dividend to decimal for understanding:**
$$\text{(13AF9)}_{16} = 1 \times 16^4 + 3 \times 16^3 + A \times 16^2 + F \times 16^1 + 9 \times 16^0$$
$$= 1 \times 65536 + 3 \times 4096 + 10 \times 256 + 15 \times 16 + 9 = 65536 + 12288 + 2560 + 240 + 9 = 80633_{10}$$
4. **Perform division in decimal:**
$$80633 \div 154 = 523 \text{ remainder } 5B_{16} \text{ (to be verified)}$$
5. **Convert quotient back to hexadecimal:**
$$523_{10} = 2 \times 256 + 0 \times 16 + 11 = \text{(20B)}_{16}$$
6. **Calculate remainder in decimal:**
$$80633 - 154 \times 523 = 80633 - 80542 = 91_{10}$$
7. **Convert remainder to hexadecimal:**
$$91_{10} = 5 \times 16 + 11 = \text{(5B)}_{16}$$
8. **Conclusion:**
$$\frac{\text{(13AF9)}_{16}}{\text{(9A)}_{16}} = \text{(20B)}_{16} \text{ remainder } \text{(5B)}_{16}$$
Hexadecimal division follows the same principles as decimal division but uses base 16 arithmetic.
**Final answer:** Quotient = $\text{(20B)}_{16}$, Remainder = $\text{(5B)}_{16}$.